4u^2-85u+441=0

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Solution for 4u^2-85u+441=0 equation:



4u^2-85u+441=0
a = 4; b = -85; c = +441;
Δ = b2-4ac
Δ = -852-4·4·441
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-85)-13}{2*4}=\frac{72}{8} =9 $
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-85)+13}{2*4}=\frac{98}{8} =12+1/4 $

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